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2016431540353 is a prime number
BaseRepresentation
bin11101010101111100101…
…011111000100010000001
321010202202120200120211201
4131111330223320202001
5231014122433242403
64142200313541201
7265453024202356
oct35257453704201
97122676616751
102016431540353
117081890442aa
1228696aa14801
131181c1853009
146d84ac7662d
15376ba81721d
hex1d57caf8881

2016431540353 has 2 divisors, whose sum is σ = 2016431540354. Its totient is φ = 2016431540352.

The previous prime is 2016431540311. The next prime is 2016431540359. The reversal of 2016431540353 is 3530451346102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2008421827344 + 8009713009 = 1417188^2 + 89497^2 .

It is a cyclic number.

It is not a de Polignac number, because 2016431540353 - 213 = 2016431532161 is a prime.

It is not a weakly prime, because it can be changed into another prime (2016431540359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1008215770176 + 1008215770177.

It is an arithmetic number, because the mean of its divisors is an integer number (1008215770177).

Almost surely, 22016431540353 is an apocalyptic number.

It is an amenable number.

2016431540353 is a deficient number, since it is larger than the sum of its proper divisors (1).

2016431540353 is an equidigital number, since it uses as much as digits as its factorization.

2016431540353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 37.

Adding to 2016431540353 its reverse (3530451346102), we get a palindrome (5546882886455).

The spelling of 2016431540353 in words is "two trillion, sixteen billion, four hundred thirty-one million, five hundred forty thousand, three hundred fifty-three".