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20183150137 is a prime number
BaseRepresentation
bin10010110011000000…
…100110111000111001
31221002121011021000011
4102303000212320321
5312313341301022
613134430541521
71313104642213
oct226300467071
957077137004
1020183150137
118617953477
123ab33678a1
131b986125b7
14d9675d5b3
157d1d97977
hex4b3026e39

20183150137 has 2 divisors, whose sum is σ = 20183150138. Its totient is φ = 20183150136.

The previous prime is 20183150123. The next prime is 20183150147. The reversal of 20183150137 is 73105138102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12908595456 + 7274554681 = 113616^2 + 85291^2 .

It is a cyclic number.

It is not a de Polignac number, because 20183150137 - 215 = 20183117369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20183150099 and 20183150108.

It is not a weakly prime, because it can be changed into another prime (20183150107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10091575068 + 10091575069.

It is an arithmetic number, because the mean of its divisors is an integer number (10091575069).

Almost surely, 220183150137 is an apocalyptic number.

It is an amenable number.

20183150137 is a deficient number, since it is larger than the sum of its proper divisors (1).

20183150137 is an equidigital number, since it uses as much as digits as its factorization.

20183150137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5040, while the sum is 31.

Adding to 20183150137 its reverse (73105138102), we get a palindrome (93288288239).

The spelling of 20183150137 in words is "twenty billion, one hundred eighty-three million, one hundred fifty thousand, one hundred thirty-seven".