Base | Representation |
---|---|
bin | 1001001011101101011010… |
… | …01101101111101101001011 |
3 | 2122111111002000220002110011 |
4 | 10211312231031233231023 |
5 | 10121322341103221024 |
6 | 110540442040532351 |
7 | 4152635633060104 |
oct | 445665515575513 |
9 | 78444060802404 |
10 | 20193547320139 |
11 | 6486043021366 |
12 | 232178a1810b7 |
13 | b3632180c73b |
14 | 4db5313753ab |
15 | 250431aa5094 |
hex | 125dad36fb4b |
20193547320139 has 2 divisors, whose sum is σ = 20193547320140. Its totient is φ = 20193547320138.
The previous prime is 20193547320047. The next prime is 20193547320161. The reversal of 20193547320139 is 93102374539102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20193547320139 - 227 = 20193413102411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20193547320092 and 20193547320101.
It is not a weakly prime, because it can be changed into another prime (20193547320839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10096773660069 + 10096773660070.
It is an arithmetic number, because the mean of its divisors is an integer number (10096773660070).
Almost surely, 220193547320139 is an apocalyptic number.
20193547320139 is a deficient number, since it is larger than the sum of its proper divisors (1).
20193547320139 is an equidigital number, since it uses as much as digits as its factorization.
20193547320139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1224720, while the sum is 49.
The spelling of 20193547320139 in words is "twenty trillion, one hundred ninety-three billion, five hundred forty-seven million, three hundred twenty thousand, one hundred thirty-nine".
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