Base | Representation |
---|---|
bin | 1001001011101111110011… |
… | …01011001010111000011011 |
3 | 2122111121101102200011102001 |
4 | 10211313321223022320123 |
5 | 10121333003001231133 |
6 | 110541213223221431 |
7 | 4153012500406042 |
oct | 445677153127033 |
9 | 78447342604361 |
10 | 20194830102043 |
11 | 64866411293a3 |
12 | 2321a878a7877 |
13 | b364974c959c |
14 | 4db613893559 |
15 | 2504a94e387d |
hex | 125df9acae1b |
20194830102043 has 2 divisors, whose sum is σ = 20194830102044. Its totient is φ = 20194830102042.
The previous prime is 20194830101989. The next prime is 20194830102059. The reversal of 20194830102043 is 34020103849102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20194830102043 - 229 = 20194293231131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20194830101993 and 20194830102011.
It is not a weakly prime, because it can be changed into another prime (20194830102743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10097415051021 + 10097415051022.
It is an arithmetic number, because the mean of its divisors is an integer number (10097415051022).
Almost surely, 220194830102043 is an apocalyptic number.
20194830102043 is a deficient number, since it is larger than the sum of its proper divisors (1).
20194830102043 is an equidigital number, since it uses as much as digits as its factorization.
20194830102043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 37.
The spelling of 20194830102043 in words is "twenty trillion, one hundred ninety-four billion, eight hundred thirty million, one hundred two thousand, forty-three".
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