Base | Representation |
---|---|
bin | 11101011001010010000… |
… | …110010011001001010001 |
3 | 21011010000002222101201220 |
4 | 131121102012103021101 |
5 | 231043441033341423 |
6 | 4143551455515253 |
7 | 265640531541504 |
oct | 35312206231121 |
9 | 7133002871656 |
10 | 2020012012113 |
11 | 709756134777 |
12 | 2875a9b28b29 |
13 | 118642586664 |
14 | 6daaa5c113b |
15 | 37829d1c9e3 |
hex | 1d652193251 |
2020012012113 has 8 divisors (see below), whose sum is σ = 2700851716800. Its totient is φ = 1342923491088.
The previous prime is 2020012012097. The next prime is 2020012012121. The reversal of 2020012012113 is 3112102100202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2020012012113 - 24 = 2020012012097 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2020012012092 and 2020012012101.
It is not an unprimeable number, because it can be changed into a prime (2020012011113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 937794658 + ... + 937796811.
It is an arithmetic number, because the mean of its divisors is an integer number (337606464600).
Almost surely, 22020012012113 is an apocalyptic number.
It is an amenable number.
2020012012113 is a deficient number, since it is larger than the sum of its proper divisors (680839704687).
2020012012113 is a wasteful number, since it uses less digits than its factorization.
2020012012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1875591831.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 2020012012113 its reverse (3112102100202), we get a palindrome (5132114112315).
The spelling of 2020012012113 in words is "two trillion, twenty billion, twelve million, twelve thousand, one hundred thirteen".
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