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2020012012113 = 33591875591469
BaseRepresentation
bin11101011001010010000…
…110010011001001010001
321011010000002222101201220
4131121102012103021101
5231043441033341423
64143551455515253
7265640531541504
oct35312206231121
97133002871656
102020012012113
11709756134777
122875a9b28b29
13118642586664
146daaa5c113b
1537829d1c9e3
hex1d652193251

2020012012113 has 8 divisors (see below), whose sum is σ = 2700851716800. Its totient is φ = 1342923491088.

The previous prime is 2020012012097. The next prime is 2020012012121. The reversal of 2020012012113 is 3112102100202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2020012012113 - 24 = 2020012012097 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2020012012092 and 2020012012101.

It is not an unprimeable number, because it can be changed into a prime (2020012011113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 937794658 + ... + 937796811.

It is an arithmetic number, because the mean of its divisors is an integer number (337606464600).

Almost surely, 22020012012113 is an apocalyptic number.

It is an amenable number.

2020012012113 is a deficient number, since it is larger than the sum of its proper divisors (680839704687).

2020012012113 is a wasteful number, since it uses less digits than its factorization.

2020012012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1875591831.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 2020012012113 its reverse (3112102100202), we get a palindrome (5132114112315).

The spelling of 2020012012113 in words is "two trillion, twenty billion, twelve million, twelve thousand, one hundred thirteen".

Divisors: 1 3 359 1077 1875591469 5626774407 673337337371 2020012012113