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20202013333042 = 210101006666521
BaseRepresentation
bin1001001011111101001011…
…10101000001011000110010
32122112021221001012002212121
410211332211311001120302
510121442210403124132
6110544402104544454
74153355503021342
oct445764565013062
978467831162777
1020202013333042
116489697952142
12232335148212a
13b37070767c28
144dbad58a8d22
15250779e53497
hex125fa5d41632

20202013333042 has 4 divisors (see below), whose sum is σ = 30303019999566. Its totient is φ = 10101006666520.

The previous prime is 20202013333039. The next prime is 20202013333069. The reversal of 20202013333042 is 24033331020202.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 19268140423401 + 933872909641 = 4389549^2 + 966371^2 .

It is a junction number, because it is equal to n+sod(n) for n = 20202013332998 and 20202013333016.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050503333259 + ... + 5050503333262.

Almost surely, 220202013333042 is an apocalyptic number.

20202013333042 is a deficient number, since it is larger than the sum of its proper divisors (10101006666524).

20202013333042 is a wasteful number, since it uses less digits than its factorization.

20202013333042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10101006666523.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 20202013333042 its reverse (24033331020202), we get a palindrome (44235344353244).

The spelling of 20202013333042 in words is "twenty trillion, two hundred two billion, thirteen million, three hundred thirty-three thousand, forty-two".

Divisors: 1 2 10101006666521 20202013333042