Base | Representation |
---|---|
bin | 11101011001011111111… |
… | …100001100011101011001 |
3 | 21011010121021222000102111 |
4 | 131121133330030131121 |
5 | 231044430011304223 |
6 | 4144030513232321 |
7 | 265646351512351 |
oct | 35313774143531 |
9 | 7133537860374 |
10 | 2020244244313 |
11 | 709865232209 |
12 | 2876538626a1 |
13 | 11867b717969 |
14 | 6dacd393b61 |
15 | 378403e230d |
hex | 1d65ff0c759 |
2020244244313 has 2 divisors, whose sum is σ = 2020244244314. Its totient is φ = 2020244244312.
The previous prime is 2020244244269. The next prime is 2020244244331. The reversal of 2020244244313 is 3134424420202.
Together with next prime (2020244244331) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1910662059289 + 109582185024 = 1382267^2 + 331032^2 .
It is a cyclic number.
It is not a de Polignac number, because 2020244244313 - 237 = 1882805290841 is a prime.
It is not a weakly prime, because it can be changed into another prime (2020244244353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010122122156 + 1010122122157.
It is an arithmetic number, because the mean of its divisors is an integer number (1010122122157).
Almost surely, 22020244244313 is an apocalyptic number.
It is an amenable number.
2020244244313 is a deficient number, since it is larger than the sum of its proper divisors (1).
2020244244313 is an equidigital number, since it uses as much as digits as its factorization.
2020244244313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 2020244244313 its reverse (3134424420202), we get a palindrome (5154668664515).
The spelling of 2020244244313 in words is "two trillion, twenty billion, two hundred forty-four million, two hundred forty-four thousand, three hundred thirteen".
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