Base | Representation |
---|---|
bin | 1001001100000011101011… |
… | …10010011010111110100001 |
3 | 2122112121221012022121201120 |
4 | 10212001311302122332201 |
5 | 10122021332042443403 |
6 | 110550140221522453 |
7 | 4153541116610601 |
oct | 446016562327641 |
9 | 78477835277646 |
10 | 20205502312353 |
11 | 6490118331a16 |
12 | 2323b65a13429 |
13 | b374a8546227 |
14 | 4dbd46dd8c01 |
15 | 2508d13d4e53 |
hex | 126075c9afa1 |
20205502312353 has 4 divisors (see below), whose sum is σ = 26940669749808. Its totient is φ = 13470334874900.
The previous prime is 20205502312349. The next prime is 20205502312361. The reversal of 20205502312353 is 35321320550202.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20205502312353 - 22 = 20205502312349 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20205502312343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3367583718723 + ... + 3367583718728.
It is an arithmetic number, because the mean of its divisors is an integer number (6735167437452).
Almost surely, 220205502312353 is an apocalyptic number.
It is an amenable number.
20205502312353 is a deficient number, since it is larger than the sum of its proper divisors (6735167437455).
20205502312353 is an equidigital number, since it uses as much as digits as its factorization.
20205502312353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6735167437454.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 20205502312353 its reverse (35321320550202), we get a palindrome (55526822862555).
The spelling of 20205502312353 in words is "twenty trillion, two hundred five billion, five hundred two million, three hundred twelve thousand, three hundred fifty-three".
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