Base | Representation |
---|---|
bin | 11101011010001110110… |
… | …101110100001001110001 |
3 | 21011012122010120110221021 |
4 | 131122032311310021301 |
5 | 231103032430213131 |
6 | 4144240542255441 |
7 | 266005014625321 |
oct | 35321665641161 |
9 | 7135563513837 |
10 | 2021031101041 |
11 | 70a129406327 |
12 | 287833287581 |
13 | 118775748364 |
14 | 6db65a9b281 |
15 | 3788951ee11 |
hex | 1d68ed74271 |
2021031101041 has 2 divisors, whose sum is σ = 2021031101042. Its totient is φ = 2021031101040.
The previous prime is 2021031100969. The next prime is 2021031101053. The reversal of 2021031101041 is 1401011301202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1719625709025 + 301405392016 = 1311345^2 + 549004^2 .
It is a cyclic number.
It is not a de Polignac number, because 2021031101041 - 211 = 2021031098993 is a prime.
It is a super-2 number, since 2×20210311010412 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2021031101641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010515550520 + 1010515550521.
It is an arithmetic number, because the mean of its divisors is an integer number (1010515550521).
Almost surely, 22021031101041 is an apocalyptic number.
It is an amenable number.
2021031101041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021031101041 is an equidigital number, since it uses as much as digits as its factorization.
2021031101041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2021031101041 its reverse (1401011301202), we get a palindrome (3422042402243).
The spelling of 2021031101041 in words is "two trillion, twenty-one billion, thirty-one million, one hundred one thousand, forty-one".
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