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202104113 is a prime number
BaseRepresentation
bin11000000101111…
…01110100110001
3112002021221201112
430002331310301
5403214312423
632015443105
75002566551
oct1402756461
9462257645
10202104113
11a409a8a2
1257826495
1332b42c43
141cbad161
1512b22a78
hexc0bdd31

202104113 has 2 divisors, whose sum is σ = 202104114. Its totient is φ = 202104112.

The previous prime is 202104107. The next prime is 202104139. The reversal of 202104113 is 311401202.

202104113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 155550784 + 46553329 = 12472^2 + 6823^2 .

It is a cyclic number.

It is not a de Polignac number, because 202104113 - 28 = 202103857 is a prime.

It is not a weakly prime, because it can be changed into another prime (202104713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101052056 + 101052057.

It is an arithmetic number, because the mean of its divisors is an integer number (101052057).

Almost surely, 2202104113 is an apocalyptic number.

It is an amenable number.

202104113 is a deficient number, since it is larger than the sum of its proper divisors (1).

202104113 is an equidigital number, since it uses as much as digits as its factorization.

202104113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

The square root of 202104113 is about 14216.3326142856. The cubic root of 202104113 is about 586.8472186974.

Adding to 202104113 its reverse (311401202), we get a palindrome (513505315).

The spelling of 202104113 in words is "two hundred two million, one hundred four thousand, one hundred thirteen".