Base | Representation |
---|---|
bin | 1001001100001110100000… |
… | …00100100111110101000011 |
3 | 2122120011221002021100101002 |
4 | 10212013100010213311003 |
5 | 10122120231333002243 |
6 | 110552540515402215 |
7 | 4154135103261443 |
oct | 446072004476503 |
9 | 78504832240332 |
10 | 20211312000323 |
11 | 6492629797534 |
12 | 23251075b336b |
13 | b37bc306a512 |
14 | 4dc338828123 |
15 | 250b21478eb8 |
hex | 1261d0127d43 |
20211312000323 has 2 divisors, whose sum is σ = 20211312000324. Its totient is φ = 20211312000322.
The previous prime is 20211312000307. The next prime is 20211312000329. The reversal of 20211312000323 is 32300021311202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20211312000323 - 24 = 20211312000307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20211312000295 and 20211312000304.
It is not a weakly prime, because it can be changed into another prime (20211312000329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10105656000161 + 10105656000162.
It is an arithmetic number, because the mean of its divisors is an integer number (10105656000162).
Almost surely, 220211312000323 is an apocalyptic number.
20211312000323 is a deficient number, since it is larger than the sum of its proper divisors (1).
20211312000323 is an equidigital number, since it uses as much as digits as its factorization.
20211312000323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 20211312000323 its reverse (32300021311202), we get a palindrome (52511333311525).
The spelling of 20211312000323 in words is "twenty trillion, two hundred eleven billion, three hundred twelve million, three hundred twenty-three", and thus it is an aban number.
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