Base | Representation |
---|---|
bin | 11101011010100110000… |
… | …001011001001001011011 |
3 | 21011020122020101012122102 |
4 | 131122212001121021123 |
5 | 231104332010341443 |
6 | 4144343314114015 |
7 | 266020446414011 |
oct | 35324601311133 |
9 | 7136566335572 |
10 | 2021420012123 |
11 | 70a308997a46 |
12 | 28792157b90b |
13 | 1188081a6565 |
14 | 6dba15b68b1 |
15 | 378ad742cb8 |
hex | 1d6a605925b |
2021420012123 has 2 divisors, whose sum is σ = 2021420012124. Its totient is φ = 2021420012122.
The previous prime is 2021420012119. The next prime is 2021420012147. The reversal of 2021420012123 is 3212100241202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2021420012123 - 22 = 2021420012119 is a prime.
It is a super-2 number, since 2×20214200121232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2021420012095 and 2021420012104.
It is not a weakly prime, because it can be changed into another prime (2021420012153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010710006061 + 1010710006062.
It is an arithmetic number, because the mean of its divisors is an integer number (1010710006062).
Almost surely, 22021420012123 is an apocalyptic number.
2021420012123 is a deficient number, since it is larger than the sum of its proper divisors (1).
2021420012123 is an equidigital number, since it uses as much as digits as its factorization.
2021420012123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 2021420012123 its reverse (3212100241202), we get a palindrome (5233520253325).
The spelling of 2021420012123 in words is "two trillion, twenty-one billion, four hundred twenty million, twelve thousand, one hundred twenty-three".
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