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20220004113 = 36740001371
BaseRepresentation
bin10010110101001101…
…001100011100010001
31221012011111122011020
4102311031030130101
5312402310112423
613142224510053
71314033125211
oct226515143421
957164448136
1020220004113
118636735401
123b0377b329
131ba314719a
14d9b5d4241
157d52274e3
hex4b534c711

20220004113 has 4 divisors (see below), whose sum is σ = 26960005488. Its totient is φ = 13480002740.

The previous prime is 20220004111. The next prime is 20220004141. The reversal of 20220004113 is 31140002202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20220004113 - 21 = 20220004111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20220004092 and 20220004101.

It is not an unprimeable number, because it can be changed into a prime (20220004111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3370000683 + ... + 3370000688.

It is an arithmetic number, because the mean of its divisors is an integer number (6740001372).

Almost surely, 220220004113 is an apocalyptic number.

It is an amenable number.

20220004113 is a deficient number, since it is larger than the sum of its proper divisors (6740001375).

20220004113 is an equidigital number, since it uses as much as digits as its factorization.

20220004113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6740001374.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 20220004113 its reverse (31140002202), we get a palindrome (51360006315).

The spelling of 20220004113 in words is "twenty billion, two hundred twenty million, four thousand, one hundred thirteen".

Divisors: 1 3 6740001371 20220004113