Base | Representation |
---|---|
bin | 11101011011001001001… |
… | …111110101110100000001 |
3 | 21011022011102102121111120 |
4 | 131123021033311310001 |
5 | 231112034304031423 |
6 | 4144522105102453 |
7 | 266041213635624 |
oct | 35331117656401 |
9 | 7138142377446 |
10 | 2022011002113 |
11 | 70a591551523 |
12 | 287a67487a29 |
13 | 1188a076908b |
14 | 6dc19c95dbb |
15 | 378e5580ee3 |
hex | 1d6c93f5d01 |
2022011002113 has 16 divisors (see below), whose sum is σ = 2816235171456. Its totient is φ = 1288022186880.
The previous prime is 2022011002061. The next prime is 2022011002139. The reversal of 2022011002113 is 3112001102202.
It is not a de Polignac number, because 2022011002113 - 29 = 2022011001601 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2022011002092 and 2022011002101.
It is not an unprimeable number, because it can be changed into a prime (2022011009113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15572758 + ... + 15702063.
It is an arithmetic number, because the mean of its divisors is an integer number (176014698216).
Almost surely, 22022011002113 is an apocalyptic number.
2022011002113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
2022011002113 is a deficient number, since it is larger than the sum of its proper divisors (794224169343).
2022011002113 is a wasteful number, since it uses less digits than its factorization.
2022011002113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31275784.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 2022011002113 its reverse (3112001102202), we get a palindrome (5134012104315).
The spelling of 2022011002113 in words is "two trillion, twenty-two billion, eleven million, two thousand, one hundred thirteen".
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