Search a number
-
+
202210120000969 is a prime number
BaseRepresentation
bin101101111110100010110110…
…010111110110010111001001
3222111222002122221022220112121
4231332202312113312113021
5203001002311210012334
61554022014031211241
760410125164335563
oct5576426627662711
9874862587286477
10202210120000969
11594809151518a3
121a819814076b21
1388aa442657072
1437d1044634333
151859e38ba4db4
hexb7e8b65f65c9

202210120000969 has 2 divisors, whose sum is σ = 202210120000970. Its totient is φ = 202210120000968.

The previous prime is 202210120000951. The next prime is 202210120001023. The reversal of 202210120000969 is 969000021012202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 201598538131600 + 611581869369 = 14198540^2 + 782037^2 .

It is a cyclic number.

It is not a de Polignac number, because 202210120000969 - 231 = 202207972517321 is a prime.

It is a super-2 number, since 2×2022101200009692 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (202210120000919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101105060000484 + 101105060000485.

It is an arithmetic number, because the mean of its divisors is an integer number (101105060000485).

Almost surely, 2202210120000969 is an apocalyptic number.

It is an amenable number.

202210120000969 is a deficient number, since it is larger than the sum of its proper divisors (1).

202210120000969 is an equidigital number, since it uses as much as digits as its factorization.

202210120000969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 34.

The spelling of 202210120000969 in words is "two hundred two trillion, two hundred ten billion, one hundred twenty million, nine hundred sixty-nine", and thus it is an aban number.