Base | Representation |
---|---|
bin | 11101011011001110101… |
… | …111001111100100000101 |
3 | 21011022101211202200200002 |
4 | 131123032233033210011 |
5 | 231112231344321013 |
6 | 4144535155331045 |
7 | 266043412632365 |
oct | 35331657174405 |
9 | 7138354680602 |
10 | 2022103120133 |
11 | 70a62954a118 |
12 | 287a922b0a85 |
13 | 1188b6880095 |
14 | 6dc281d49a5 |
15 | 378ed6ca358 |
hex | 1d6cebcf905 |
2022103120133 has 16 divisors (see below), whose sum is σ = 2155900032000. Its totient is φ = 1891052862192.
The previous prime is 2022103120109. The next prime is 2022103120181. The reversal of 2022103120133 is 3310213012202.
It is a cyclic number.
It is not a de Polignac number, because 2022103120133 - 212 = 2022103116037 is a prime.
It is a super-2 number, since 2×20221031201332 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2022103120633) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7594778 + ... + 7856516.
It is an arithmetic number, because the mean of its divisors is an integer number (134743752000).
Almost surely, 22022103120133 is an apocalyptic number.
It is an amenable number.
2022103120133 is a deficient number, since it is larger than the sum of its proper divisors (133796911867).
2022103120133 is a wasteful number, since it uses less digits than its factorization.
2022103120133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 266984.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2022103120133 its reverse (3310213012202), we get a palindrome (5332316132335).
The spelling of 2022103120133 in words is "two trillion, twenty-two billion, one hundred three million, one hundred twenty thousand, one hundred thirty-three".
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