Base | Representation |
---|---|
bin | 11101011011001111001… |
… | …110000110100111011011 |
3 | 21011022102101222200210211 |
4 | 131123033032012213123 |
5 | 231112240432204242 |
6 | 4144540044551551 |
7 | 266043541455013 |
oct | 35331716064733 |
9 | 7138371880724 |
10 | 2022111209947 |
11 | 70a633075114 |
12 | 287a94b525b7 |
13 | 1188b845335a |
14 | 6dc292dcc43 |
15 | 378ee277317 |
hex | 1d6cf3869db |
2022111209947 has 2 divisors, whose sum is σ = 2022111209948. Its totient is φ = 2022111209946.
The previous prime is 2022111209869. The next prime is 2022111209983. The reversal of 2022111209947 is 7499021112202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2022111209947 - 215 = 2022111177179 is a prime.
It is not a weakly prime, because it can be changed into another prime (2022111209347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011055604973 + 1011055604974.
It is an arithmetic number, because the mean of its divisors is an integer number (1011055604974).
Almost surely, 22022111209947 is an apocalyptic number.
2022111209947 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022111209947 is an equidigital number, since it uses as much as digits as its factorization.
2022111209947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 40.
The spelling of 2022111209947 in words is "two trillion, twenty-two billion, one hundred eleven million, two hundred nine thousand, nine hundred forty-seven".
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