Base | Representation |
---|---|
bin | 11101011011001111101… |
… | …111101000111000111001 |
3 | 21011022110000112022222101 |
4 | 131123033233220320321 |
5 | 231112300210013311 |
6 | 4144541001223401 |
7 | 266044006261105 |
oct | 35331757507071 |
9 | 7138400468871 |
10 | 2022120001081 |
11 | 70a63802a014 |
12 | 287a97a91b61 |
13 | 1188ba2108cb |
14 | 6dc2a54a905 |
15 | 378eee11ec1 |
hex | 1d6cfbe8e39 |
2022120001081 has 2 divisors, whose sum is σ = 2022120001082. Its totient is φ = 2022120001080.
The previous prime is 2022120001049. The next prime is 2022120001147. The reversal of 2022120001081 is 1801000212202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2014824108025 + 7295893056 = 1419445^2 + 85416^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022120001081 - 25 = 2022120001049 is a prime.
It is a super-2 number, since 2×20221200010812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2022126001081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011060000540 + 1011060000541.
It is an arithmetic number, because the mean of its divisors is an integer number (1011060000541).
Almost surely, 22022120001081 is an apocalyptic number.
It is an amenable number.
2022120001081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022120001081 is an equidigital number, since it uses as much as digits as its factorization.
2022120001081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 2022120001081 its reverse (1801000212202), we get a palindrome (3823120213283).
The spelling of 2022120001081 in words is "two trillion, twenty-two billion, one hundred twenty million, one thousand, eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •