Base | Representation |
---|---|
bin | 1001001100100001010111… |
… | …10100111000000101000001 |
3 | 2122121011002000100122110022 |
4 | 10212100223310320011001 |
5 | 10122302002433423131 |
6 | 111001334001543225 |
7 | 4154644111063535 |
oct | 446205364700501 |
9 | 78534060318408 |
10 | 20221441311041 |
11 | 64969574a2603 |
12 | 2327073944b15 |
13 | b38b487917b9 |
14 | 4dca19c0bbc5 |
15 | 25101587b37b |
hex | 12642bd38141 |
20221441311041 has 2 divisors, whose sum is σ = 20221441311042. Its totient is φ = 20221441311040.
The previous prime is 20221441310933. The next prime is 20221441311059. The reversal of 20221441311041 is 14011314412202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17466306091441 + 2755135219600 = 4179271^2 + 1659860^2 .
It is a cyclic number.
It is not a de Polignac number, because 20221441311041 - 214 = 20221441294657 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20221441311041.
It is not a weakly prime, because it can be changed into another prime (20221441311091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10110720655520 + 10110720655521.
It is an arithmetic number, because the mean of its divisors is an integer number (10110720655521).
Almost surely, 220221441311041 is an apocalyptic number.
It is an amenable number.
20221441311041 is a deficient number, since it is larger than the sum of its proper divisors (1).
20221441311041 is an equidigital number, since it uses as much as digits as its factorization.
20221441311041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 20221441311041 its reverse (14011314412202), we get a palindrome (34232755723243).
The spelling of 20221441311041 in words is "twenty trillion, two hundred twenty-one billion, four hundred forty-one million, three hundred eleven thousand, forty-one".
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