Search a number
-
+
20222011019993 is a prime number
BaseRepresentation
bin1001001100100010011011…
…10010001001001011011001
32122121012112201100212012212
410212101031302021023121
510122304134310114433
6111001510312444505
74154664166402556
oct446211562111331
978535481325185
1020222011019993
11649711a041352
1223271b26a9735
13b38c09812aa3
144dca7174ba2d
1525104a8b3d48
hex12644dc892d9

20222011019993 has 2 divisors, whose sum is σ = 20222011019994. Its totient is φ = 20222011019992.

The previous prime is 20222011019957. The next prime is 20222011020073. The reversal of 20222011019993 is 39991011022202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14939129423689 + 5282881596304 = 3865117^2 + 2298452^2 .

It is a cyclic number.

It is not a de Polignac number, because 20222011019993 - 210 = 20222011018969 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20222011019993.

It is not a weakly prime, because it can be changed into another prime (20222011013993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10111005509996 + 10111005509997.

It is an arithmetic number, because the mean of its divisors is an integer number (10111005509997).

Almost surely, 220222011019993 is an apocalyptic number.

It is an amenable number.

20222011019993 is a deficient number, since it is larger than the sum of its proper divisors (1).

20222011019993 is an equidigital number, since it uses as much as digits as its factorization.

20222011019993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 41.

The spelling of 20222011019993 in words is "twenty trillion, two hundred twenty-two billion, eleven million, nineteen thousand, nine hundred ninety-three".