Base | Representation |
---|---|
bin | 11101011011010100100… |
… | …101000011001010011001 |
3 | 21011022122200011011010121 |
4 | 131123110211003022121 |
5 | 231112431441024233 |
6 | 4144553015513241 |
7 | 266046012556534 |
oct | 35332445031231 |
9 | 7138580134117 |
10 | 2022201111193 |
11 | 70a67989926a |
12 | 287abb088821 |
13 | 118900c6c363 |
14 | 6dc37221a1b |
15 | 379070d492d |
hex | 1d6d4943299 |
2022201111193 has 2 divisors, whose sum is σ = 2022201111194. Its totient is φ = 2022201111192.
The previous prime is 2022201111173. The next prime is 2022201111251. The reversal of 2022201111193 is 3911111022202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1960201605184 + 61999506009 = 1400072^2 + 248997^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022201111193 - 237 = 1884762157721 is a prime.
It is a super-2 number, since 2×20222011111932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2022201111103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011100555596 + 1011100555597.
It is an arithmetic number, because the mean of its divisors is an integer number (1011100555597).
Almost surely, 22022201111193 is an apocalyptic number.
It is an amenable number.
2022201111193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022201111193 is an equidigital number, since it uses as much as digits as its factorization.
2022201111193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 2022201111193 its reverse (3911111022202), we get a palindrome (5933312133395).
The spelling of 2022201111193 in words is "two trillion, twenty-two billion, two hundred one million, one hundred eleven thousand, one hundred ninety-three".
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