2022410041131 has 16 divisors (see below), whose sum is σ = 2714486600960. Its totient is φ = 1339303960800.

The previous prime is 2022410041087. The next prime is 2022410041153. The reversal of 2022410041131 is 1311400142202.

It is not a de Polignac number, because 2022410041131 - 2¹³ = 2022410032939 is a prime.

It is a super-3 number, since 3×2022410041131³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2022410041098 and 2022410041107.

It is not an unprimeable number, because it can be changed into a prime (2022410046131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26498181 + ... + 26574393.

It is an arithmetic number, because the mean of its divisors is an integer number (169655412560).

Almost surely, 2^{2022410041131} is an apocalyptic number.

2022410041131 is a deficient number, since it is larger than the sum of its proper divisors (692076559829).

2022410041131 is a wasteful number, since it uses less digits than its factorization.

2022410041131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134946.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 2022410041131 its reverse (1311400142202), we get a palindrome (3333810183333).

The spelling of 2022410041131 in words is "two trillion, twenty-two billion, four hundred ten million, forty-one thousand, one hundred thirty-one".