Base | Representation |
---|---|
bin | 11101011011100001000… |
… | …010000011011101000001 |
3 | 21011100012020021220011021 |
4 | 131123201002003131001 |
5 | 231113343432304103 |
6 | 4145025441545441 |
7 | 266054130466015 |
oct | 35334102033501 |
9 | 7140166256137 |
10 | 2022410041153 |
11 | 70a776820457 |
12 | 287b59045281 |
13 | 118935332158 |
14 | 6dc56c8a545 |
15 | 3791a604bbd |
hex | 1d6e1083741 |
2022410041153 has 2 divisors, whose sum is σ = 2022410041154. Its totient is φ = 2022410041152.
The previous prime is 2022410041087. The next prime is 2022410041187. The reversal of 2022410041153 is 3511400142202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1223704988944 + 798705052209 = 1106212^2 + 893703^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2022410041153 is a prime.
It is not a weakly prime, because it can be changed into another prime (2022410071153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011205020576 + 1011205020577.
It is an arithmetic number, because the mean of its divisors is an integer number (1011205020577).
Almost surely, 22022410041153 is an apocalyptic number.
It is an amenable number.
2022410041153 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022410041153 is an equidigital number, since it uses as much as digits as its factorization.
2022410041153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 2022410041153 its reverse (3511400142202), we get a palindrome (5533810183355).
The spelling of 2022410041153 in words is "two trillion, twenty-two billion, four hundred ten million, forty-one thousand, one hundred fifty-three".
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