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2022410041153 is a prime number
BaseRepresentation
bin11101011011100001000…
…010000011011101000001
321011100012020021220011021
4131123201002003131001
5231113343432304103
64145025441545441
7266054130466015
oct35334102033501
97140166256137
102022410041153
1170a776820457
12287b59045281
13118935332158
146dc56c8a545
153791a604bbd
hex1d6e1083741

2022410041153 has 2 divisors, whose sum is σ = 2022410041154. Its totient is φ = 2022410041152.

The previous prime is 2022410041087. The next prime is 2022410041187. The reversal of 2022410041153 is 3511400142202.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1223704988944 + 798705052209 = 1106212^2 + 893703^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2022410041153 is a prime.

It is not a weakly prime, because it can be changed into another prime (2022410071153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011205020576 + 1011205020577.

It is an arithmetic number, because the mean of its divisors is an integer number (1011205020577).

Almost surely, 22022410041153 is an apocalyptic number.

It is an amenable number.

2022410041153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2022410041153 is an equidigital number, since it uses as much as digits as its factorization.

2022410041153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 2022410041153 its reverse (3511400142202), we get a palindrome (5533810183355).

The spelling of 2022410041153 in words is "two trillion, twenty-two billion, four hundred ten million, forty-one thousand, one hundred fifty-three".