202241005014433 has 16 divisors (see below), whose sum is σ = 252206233888896. Its totient is φ = 157551890855040.

The previous prime is 202241005014431. The next prime is 202241005014481. The reversal of 202241005014433 is 334410500142202.

It is not a de Polignac number, because 202241005014433 - 2¹ = 202241005014431 is a prime.

It is a super-2 number, since 2×202241005014433² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 202241005014395 and 202241005014404.

It is not an unprimeable number, because it can be changed into a prime (202241005014431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 320538316 + ... + 321168637.

It is an arithmetic number, because the mean of its divisors is an integer number (15762889618056).

Almost surely, 2^{202241005014433} is an apocalyptic number.

It is an amenable number.

202241005014433 is a deficient number, since it is larger than the sum of its proper divisors (49965228874463).

202241005014433 is a wasteful number, since it uses less digits than its factorization.

202241005014433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 641711064.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 202241005014433 its reverse (334410500142202), we get a palindrome (536651505156635).

The spelling of 202241005014433 in words is "two hundred two trillion, two hundred forty-one billion, five million, fourteen thousand, four hundred thirty-three".