Base | Representation |
---|---|
bin | 11101011011100011000… |
… | …000010010110111100001 |
3 | 21011100021112120012121022 |
4 | 131123203000102313201 |
5 | 231113430420300213 |
6 | 4145033023135225 |
7 | 266055011666621 |
oct | 35334300226741 |
9 | 7140245505538 |
10 | 2022443134433 |
11 | 70a793473977 |
12 | 287b68144515 |
13 | 11893c14b087 |
14 | 6dc5b422881 |
15 | 3791d490308 |
hex | 1d6e3012de1 |
2022443134433 has 2 divisors, whose sum is σ = 2022443134434. Its totient is φ = 2022443134432.
The previous prime is 2022443134423. The next prime is 2022443134487. The reversal of 2022443134433 is 3344313442202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1394177647009 + 628265487424 = 1180753^2 + 792632^2 .
It is a cyclic number.
It is not a de Polignac number, because 2022443134433 - 214 = 2022443118049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2022443134393 and 2022443134402.
It is not a weakly prime, because it can be changed into another prime (2022443134423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011221567216 + 1011221567217.
It is an arithmetic number, because the mean of its divisors is an integer number (1011221567217).
Almost surely, 22022443134433 is an apocalyptic number.
It is an amenable number.
2022443134433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022443134433 is an equidigital number, since it uses as much as digits as its factorization.
2022443134433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 35.
Adding to 2022443134433 its reverse (3344313442202), we get a palindrome (5366756576635).
The spelling of 2022443134433 in words is "two trillion, twenty-two billion, four hundred forty-three million, one hundred thirty-four thousand, four hundred thirty-three".
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