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202244414113 = 728892059159
BaseRepresentation
bin1011110001011010110…
…1001101101010100001
3201100000202112201212001
42330112231031222201
511303144032222423
6232524303404001
720416543104250
oct2742655155241
9640022481761
10202244414113
11788537767a5
12332432b3601
13160c1301571
149b08200797
1553da515cad
hex2f16b4daa1

202244414113 has 4 divisors (see below), whose sum is σ = 231136473280. Its totient is φ = 173352354948.

The previous prime is 202244414107. The next prime is 202244414117. The reversal of 202244414113 is 311414442202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 202244414113 - 213 = 202244405921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (202244414117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14446029573 + ... + 14446029586.

It is an arithmetic number, because the mean of its divisors is an integer number (57784118320).

Almost surely, 2202244414113 is an apocalyptic number.

It is an amenable number.

202244414113 is a deficient number, since it is larger than the sum of its proper divisors (28892059167).

202244414113 is an equidigital number, since it uses as much as digits as its factorization.

202244414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28892059166.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 202244414113 its reverse (311414442202), we get a palindrome (513658856315).

The spelling of 202244414113 in words is "two hundred two billion, two hundred forty-four million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 7 28892059159 202244414113