Base | Representation |
---|---|
bin | 11101011011101000110… |
… | …011011111101000100011 |
3 | 21011100112022122221200201 |
4 | 131123220303133220203 |
5 | 231114130323122042 |
6 | 4145050420530031 |
7 | 266060303046601 |
oct | 35335063375043 |
9 | 7140468587621 |
10 | 2022540442147 |
11 | 70a833396675 |
12 | 287b94850917 |
13 | 11895635b2c4 |
14 | 6dc6a312871 |
15 | 37926cb21b7 |
hex | 1d6e8cdfa23 |
2022540442147 has 2 divisors, whose sum is σ = 2022540442148. Its totient is φ = 2022540442146.
The previous prime is 2022540442049. The next prime is 2022540442159. The reversal of 2022540442147 is 7412440452202.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2022540442147 is a prime.
It is not a weakly prime, because it can be changed into another prime (2022540442187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011270221073 + 1011270221074.
It is an arithmetic number, because the mean of its divisors is an integer number (1011270221074).
Almost surely, 22022540442147 is an apocalyptic number.
2022540442147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2022540442147 is an equidigital number, since it uses as much as digits as its factorization.
2022540442147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 143360, while the sum is 37.
Adding to 2022540442147 its reverse (7412440452202), we get a palindrome (9434980894349).
The spelling of 2022540442147 in words is "two trillion, twenty-two billion, five hundred forty million, four hundred forty-two thousand, one hundred forty-seven".
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