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202303311313 = 1195916916407
BaseRepresentation
bin1011110001101000110…
…1111000110111010001
3201100011212101000121211
42330122031320313101
511303304121430223
6232534210020121
720421156526225
oct2743215706721
9640155330554
10202303311313
1178883a44074
123325ab77641
131610058358c
149b11d72785
1553e079bd0d
hex2f1a378dd1

202303311313 has 4 divisors (see below), whose sum is σ = 202320239680. Its totient is φ = 202286382948.

The previous prime is 202303311253. The next prime is 202303311341. The reversal of 202303311313 is 313113303202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-202303311313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (202303311373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8446245 + ... + 8470162.

It is an arithmetic number, because the mean of its divisors is an integer number (50580059920).

Almost surely, 2202303311313 is an apocalyptic number.

It is an amenable number.

202303311313 is a deficient number, since it is larger than the sum of its proper divisors (16928367).

202303311313 is a wasteful number, since it uses less digits than its factorization.

202303311313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16928366.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 202303311313 its reverse (313113303202), we get a palindrome (515416614515).

The spelling of 202303311313 in words is "two hundred two billion, three hundred three million, three hundred eleven thousand, three hundred thirteen".

Divisors: 1 11959 16916407 202303311313