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2023044104121 = 3679957991751
BaseRepresentation
bin11101011100000110110…
…100110011111110111001
321011101211102101122000220
4131130012310303332321
5231121143242312441
64145212412050253
7266105630105055
oct35340664637671
97141742348026
102023044104121
1170aa71724337
122880b5463989
13118a067c6141
146dcb717cc65
1537956100466
hex1d706d33fb9

2023044104121 has 8 divisors (see below), whose sum is σ = 2697398825664. Its totient is φ = 1348692726000.

The previous prime is 2023044104093. The next prime is 2023044104129. The reversal of 2023044104121 is 1214014403202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2023044104121 - 25 = 2023044104089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2023044104091 and 2023044104100.

It is not an unprimeable number, because it can be changed into a prime (2023044104129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1543996 + ... + 2535746.

It is an arithmetic number, because the mean of its divisors is an integer number (337174853208).

Almost surely, 22023044104121 is an apocalyptic number.

It is an amenable number.

2023044104121 is a deficient number, since it is larger than the sum of its proper divisors (674354721543).

2023044104121 is an equidigital number, since it uses as much as digits as its factorization.

2023044104121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1671711.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 2023044104121 its reverse (1214014403202), we get a palindrome (3237058507323).

The spelling of 2023044104121 in words is "two trillion, twenty-three billion, forty-four million, one hundred four thousand, one hundred twenty-one".

Divisors: 1 3 679957 991751 2039871 2975253 674348034707 2023044104121