Base | Representation |
---|---|
bin | 101101111111111010101100… |
… | …010010100100011111110011 |
3 | 222112022010010021021200022111 |
4 | 231333322230102210133303 |
5 | 203004023443133003202 |
6 | 1554133213214550151 |
7 | 60420004422223303 |
oct | 5577725422443763 |
9 | 875263107250274 |
10 | 202304440125427 |
11 | 59507916426382 |
12 | 1a833b57808357 |
13 | 88b62c44c37b3 |
14 | 37d58311b7603 |
15 | 185c60943d6d7 |
hex | b7feac4a47f3 |
202304440125427 has 2 divisors, whose sum is σ = 202304440125428. Its totient is φ = 202304440125426.
The previous prime is 202304440125311. The next prime is 202304440125493. The reversal of 202304440125427 is 724521044403202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 202304440125427 - 27 = 202304440125299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 202304440125427.
It is not a weakly prime, because it can be changed into another prime (202304440126427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101152220062713 + 101152220062714.
It is an arithmetic number, because the mean of its divisors is an integer number (101152220062714).
Almost surely, 2202304440125427 is an apocalyptic number.
202304440125427 is a deficient number, since it is larger than the sum of its proper divisors (1).
202304440125427 is an equidigital number, since it uses as much as digits as its factorization.
202304440125427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 430080, while the sum is 40.
Adding to 202304440125427 its reverse (724521044403202), we get a palindrome (926825484528629).
The spelling of 202304440125427 in words is "two hundred two trillion, three hundred four billion, four hundred forty million, one hundred twenty-five thousand, four hundred twenty-seven".
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