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2023054422131 is a prime number
BaseRepresentation
bin11101011100000111011…
…100001011000001110011
321011101212010210211200102
4131130013130023001303
5231121203413002011
64145213421143015
7266106113600531
oct35340734130163
97141763724612
102023054422131
1170aa77531416
122880b89baa6b
13118a08999682
146dcb86a7151
1537956e8c73b
hex1d70770b073

2023054422131 has 2 divisors, whose sum is σ = 2023054422132. Its totient is φ = 2023054422130.

The previous prime is 2023054422121. The next prime is 2023054422167. The reversal of 2023054422131 is 1312244503202.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2023054422131 is a prime.

It is a super-2 number, since 2×20230544221312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2023054422094 and 2023054422103.

It is not a weakly prime, because it can be changed into another prime (2023054422121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011527211065 + 1011527211066.

It is an arithmetic number, because the mean of its divisors is an integer number (1011527211066).

Almost surely, 22023054422131 is an apocalyptic number.

2023054422131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023054422131 is an equidigital number, since it uses as much as digits as its factorization.

2023054422131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 2023054422131 its reverse (1312244503202), we get a palindrome (3335298925333).

The spelling of 2023054422131 in words is "two trillion, twenty-three billion, fifty-four million, four hundred twenty-two thousand, one hundred thirty-one".