Base | Representation |
---|---|
bin | 11101011100001011011… |
… | …010101001001001101001 |
3 | 21011102000210022221210112 |
4 | 131130023122221021221 |
5 | 231121323002130324 |
6 | 4145224203024105 |
7 | 266110553603423 |
oct | 35341332511151 |
9 | 7142023287715 |
10 | 2023121130089 |
11 | 710001154064 |
12 | 28811720b035 |
13 | 118a19754937 |
14 | 6dcc34ad813 |
15 | 3795cc67c0e |
hex | 1d70b6a9269 |
2023121130089 has 2 divisors, whose sum is σ = 2023121130090. Its totient is φ = 2023121130088.
The previous prime is 2023121130073. The next prime is 2023121130133. The reversal of 2023121130089 is 9800311213202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1408653275689 + 614467854400 = 1186867^2 + 783880^2 .
It is a cyclic number.
It is not a de Polignac number, because 2023121130089 - 24 = 2023121130073 is a prime.
It is a super-2 number, since 2×20231211300892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2023121130689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011560565044 + 1011560565045.
It is an arithmetic number, because the mean of its divisors is an integer number (1011560565045).
Almost surely, 22023121130089 is an apocalyptic number.
It is an amenable number.
2023121130089 is a deficient number, since it is larger than the sum of its proper divisors (1).
2023121130089 is an equidigital number, since it uses as much as digits as its factorization.
2023121130089 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 2023121130089 in words is "two trillion, twenty-three billion, one hundred twenty-one million, one hundred thirty thousand, eighty-nine".
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