Base | Representation |
---|---|
bin | 11101011100001100000… |
… | …000101101101110010011 |
3 | 21011102001111010000001122 |
4 | 131130030000231232103 |
5 | 231121333031012131 |
6 | 4145225200552455 |
7 | 266111034461264 |
oct | 35341400555623 |
9 | 7142044100048 |
10 | 2023131110291 |
11 | 710006850365 |
12 | 28811a62272b |
13 | 118a1b83a495 |
14 | 6dcc494a96b |
15 | 3795da89d7b |
hex | 1d70c02db93 |
2023131110291 has 2 divisors, whose sum is σ = 2023131110292. Its totient is φ = 2023131110290.
The previous prime is 2023131110267. The next prime is 2023131110323. The reversal of 2023131110291 is 1920111313202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2023131110291 - 210 = 2023131109267 is a prime.
It is a super-2 number, since 2×20231311102912 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2023131110291.
It is not a weakly prime, because it can be changed into another prime (2023131110261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011565555145 + 1011565555146.
It is an arithmetic number, because the mean of its divisors is an integer number (1011565555146).
Almost surely, 22023131110291 is an apocalyptic number.
2023131110291 is a deficient number, since it is larger than the sum of its proper divisors (1).
2023131110291 is an equidigital number, since it uses as much as digits as its factorization.
2023131110291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 26.
Adding to 2023131110291 its reverse (1920111313202), we get a palindrome (3943242423493).
The spelling of 2023131110291 in words is "two trillion, twenty-three billion, one hundred thirty-one million, one hundred ten thousand, two hundred ninety-one".
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