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2023144442537 is a prime number
BaseRepresentation
bin11101011100001100110…
…011100100101010101001
321011102002102012100110112
4131130030303210222221
5231121344434130122
64145230354424105
7266111256006641
oct35341463445251
97142072170415
102023144442537
11710013327049
12288122b92035
13118a2152799a
146dcc661b521
153795ed202e2
hex1d70cce4aa9

2023144442537 has 2 divisors, whose sum is σ = 2023144442538. Its totient is φ = 2023144442536.

The previous prime is 2023144442521. The next prime is 2023144442587. The reversal of 2023144442537 is 7352444413202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1532554865296 + 490589577241 = 1237964^2 + 700421^2 .

It is a cyclic number.

It is not a de Polignac number, because 2023144442537 - 24 = 2023144442521 is a prime.

It is a super-2 number, since 2×20231444425372 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2023144442494 and 2023144442503.

It is not a weakly prime, because it can be changed into another prime (2023144442507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011572221268 + 1011572221269.

It is an arithmetic number, because the mean of its divisors is an integer number (1011572221269).

Almost surely, 22023144442537 is an apocalyptic number.

It is an amenable number.

2023144442537 is a deficient number, since it is larger than the sum of its proper divisors (1).

2023144442537 is an equidigital number, since it uses as much as digits as its factorization.

2023144442537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 645120, while the sum is 41.

Adding to 2023144442537 its reverse (7352444413202), we get a palindrome (9375588855739).

The spelling of 2023144442537 in words is "two trillion, twenty-three billion, one hundred forty-four million, four hundred forty-two thousand, five hundred thirty-seven".