Base | Representation |
---|---|
bin | 11101011100001100111… |
… | …000000111011010001001 |
3 | 21011102002111102212001012 |
4 | 131130030320013122021 |
5 | 231121400240232132 |
6 | 4145230440133305 |
7 | 266111302066616 |
oct | 35341470073211 |
9 | 7142074385035 |
10 | 2023145633417 |
11 | 710013a6a847 |
12 | 288123467235 |
13 | 118a21853a4c |
14 | 6dcc684b50d |
15 | 3795eea80b2 |
hex | 1d70ce07689 |
2023145633417 has 2 divisors, whose sum is σ = 2023145633418. Its totient is φ = 2023145633416.
The previous prime is 2023145633389. The next prime is 2023145633447. The reversal of 2023145633417 is 7143365413202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1833697847881 + 189447785536 = 1354141^2 + 435256^2 .
It is a cyclic number.
It is not a de Polignac number, because 2023145633417 - 28 = 2023145633161 is a prime.
It is not a weakly prime, because it can be changed into another prime (2023145633447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011572816708 + 1011572816709.
It is an arithmetic number, because the mean of its divisors is an integer number (1011572816709).
Almost surely, 22023145633417 is an apocalyptic number.
It is an amenable number.
2023145633417 is a deficient number, since it is larger than the sum of its proper divisors (1).
2023145633417 is an equidigital number, since it uses as much as digits as its factorization.
2023145633417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 41.
It can be divided in two parts, 2023145 and 633417, that added together give a palindrome (2656562).
The spelling of 2023145633417 in words is "two trillion, twenty-three billion, one hundred forty-five million, six hundred thirty-three thousand, four hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •