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20232113544361 is a prime number
BaseRepresentation
bin1001001100110101001111…
…11100001101110010101001
32122122011121210001021100001
410212122213330031302221
510122440332031404421
6111010301000543001
74155502430422435
oct446324774156251
978564553037301
1020232113544361
1164a0433711444
122329151a81a61
13b39b59818a64
144dd34d35b9c5
1525143c774691
hex1266a7f0dca9

20232113544361 has 2 divisors, whose sum is σ = 20232113544362. Its totient is φ = 20232113544360.

The previous prime is 20232113544353. The next prime is 20232113544443. The reversal of 20232113544361 is 16344531123202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19472636153961 + 759477390400 = 4412781^2 + 871480^2 .

It is a cyclic number.

It is not a de Polignac number, because 20232113544361 - 23 = 20232113544353 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20232113544361.

It is not a weakly prime, because it can be changed into another prime (20232113244361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10116056772180 + 10116056772181.

It is an arithmetic number, because the mean of its divisors is an integer number (10116056772181).

Almost surely, 220232113544361 is an apocalyptic number.

It is an amenable number.

20232113544361 is a deficient number, since it is larger than the sum of its proper divisors (1).

20232113544361 is an equidigital number, since it uses as much as digits as its factorization.

20232113544361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 37.

Adding to 20232113544361 its reverse (16344531123202), we get a palindrome (36576644667563).

The spelling of 20232113544361 in words is "twenty trillion, two hundred thirty-two billion, one hundred thirteen million, five hundred forty-four thousand, three hundred sixty-one".