Base | Representation |
---|---|
bin | 11101011100010111100… |
… | …000111101011000010001 |
3 | 21011102112221021112011221 |
4 | 131130113200331120101 |
5 | 231122231433044101 |
6 | 4145300253405041 |
7 | 266115600121534 |
oct | 35342740753021 |
9 | 7142487245157 |
10 | 2023324112401 |
11 | 7100a5793739 |
12 | 288173199781 |
13 | 118a4c814507 |
14 | 6dd0242aa1b |
15 | 379709b0aa1 |
hex | 1d71783d611 |
2023324112401 has 2 divisors, whose sum is σ = 2023324112402. Its totient is φ = 2023324112400.
The previous prime is 2023324112377. The next prime is 2023324112489. The reversal of 2023324112401 is 1042114233202.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1533535489600 + 489788622801 = 1238360^2 + 699849^2 .
It is a cyclic number.
It is not a de Polignac number, because 2023324112401 - 215 = 2023324079633 is a prime.
It is not a weakly prime, because it can be changed into another prime (2023324152401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1011662056200 + 1011662056201.
It is an arithmetic number, because the mean of its divisors is an integer number (1011662056201).
Almost surely, 22023324112401 is an apocalyptic number.
It is an amenable number.
2023324112401 is a deficient number, since it is larger than the sum of its proper divisors (1).
2023324112401 is an equidigital number, since it uses as much as digits as its factorization.
2023324112401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2023324112401 its reverse (1042114233202), we get a palindrome (3065438345603).
The spelling of 2023324112401 in words is "two trillion, twenty-three billion, three hundred twenty-four million, one hundred twelve thousand, four hundred one".
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