Base | Representation |
---|---|
bin | 10010110101111111… |
… | …111101011110010011 |
3 | 1221020002112202100101 |
4 | 102311333331132103 |
5 | 312414211442042 |
6 | 13143422033231 |
7 | 1314254213146 |
oct | 226577753623 |
9 | 57202482311 |
10 | 20233312147 |
11 | 86431a4984 |
12 | 3b08118817 |
13 | 1ba5b26669 |
14 | d9d29a05d |
15 | 7d64a56b7 |
hex | 4b5ffd793 |
20233312147 has 2 divisors, whose sum is σ = 20233312148. Its totient is φ = 20233312146.
The previous prime is 20233312139. The next prime is 20233312273. The reversal of 20233312147 is 74121333202.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20233312147 - 23 = 20233312139 is a prime.
It is not a weakly prime, because it can be changed into another prime (20233322147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10116656073 + 10116656074.
It is an arithmetic number, because the mean of its divisors is an integer number (10116656074).
Almost surely, 220233312147 is an apocalyptic number.
20233312147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20233312147 is an equidigital number, since it uses as much as digits as its factorization.
20233312147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 20233312147 its reverse (74121333202), we get a palindrome (94354645349).
The spelling of 20233312147 in words is "twenty billion, two hundred thirty-three million, three hundred twelve thousand, one hundred forty-seven".
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