Base | Representation |
---|---|
bin | 11101011100011101111… |
… | …100100001101101100011 |
3 | 21011102211110021220102221 |
4 | 131130131330201231203 |
5 | 231122442043034103 |
6 | 4145315110051511 |
7 | 266121350144620 |
oct | 35343574415543 |
9 | 7142743256387 |
10 | 2023432002403 |
11 | 710150684029 |
12 | 2881a3349b97 |
13 | 118a68c8b356 |
14 | 6dd128b3347 |
15 | 3797a1c31bd |
hex | 1d71df21b63 |
2023432002403 has 8 divisors (see below), whose sum is σ = 2320386189408. Its totient is φ = 1728450933504.
The previous prime is 2023432002329. The next prime is 2023432002409. The reversal of 2023432002403 is 3042002343202.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2023432002403 - 233 = 2014842067811 is a prime.
It is a super-2 number, since 2×20234320024032 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2023432002409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 493277326 + ... + 493281427.
It is an arithmetic number, because the mean of its divisors is an integer number (290048273676).
Almost surely, 22023432002403 is an apocalyptic number.
2023432002403 is a deficient number, since it is larger than the sum of its proper divisors (296954187005).
2023432002403 is an equidigital number, since it uses as much as digits as its factorization.
2023432002403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 986559053.
The product of its (nonzero) digits is 6912, while the sum is 25.
Adding to 2023432002403 its reverse (3042002343202), we get a palindrome (5065434345605).
The spelling of 2023432002403 in words is "two trillion, twenty-three billion, four hundred thirty-two million, two thousand, four hundred three".
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