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2023432002403 = 7293986558753
BaseRepresentation
bin11101011100011101111…
…100100001101101100011
321011102211110021220102221
4131130131330201231203
5231122442043034103
64145315110051511
7266121350144620
oct35343574415543
97142743256387
102023432002403
11710150684029
122881a3349b97
13118a68c8b356
146dd128b3347
153797a1c31bd
hex1d71df21b63

2023432002403 has 8 divisors (see below), whose sum is σ = 2320386189408. Its totient is φ = 1728450933504.

The previous prime is 2023432002329. The next prime is 2023432002409. The reversal of 2023432002403 is 3042002343202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2023432002403 - 233 = 2014842067811 is a prime.

It is a super-2 number, since 2×20234320024032 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2023432002409) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 493277326 + ... + 493281427.

It is an arithmetic number, because the mean of its divisors is an integer number (290048273676).

Almost surely, 22023432002403 is an apocalyptic number.

2023432002403 is a deficient number, since it is larger than the sum of its proper divisors (296954187005).

2023432002403 is an equidigital number, since it uses as much as digits as its factorization.

2023432002403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 986559053.

The product of its (nonzero) digits is 6912, while the sum is 25.

Adding to 2023432002403 its reverse (3042002343202), we get a palindrome (5065434345605).

The spelling of 2023432002403 in words is "two trillion, twenty-three billion, four hundred thirty-two million, two thousand, four hundred three".

Divisors: 1 7 293 2051 986558753 6905911271 289061714629 2023432002403