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202344041401 is a prime number
BaseRepresentation
bin1011110001110010100…
…1010000101110111001
3201100021201000022210121
42330130221100232321
511303400033311101
6232542223013241
720422162654645
oct2743451205671
9640251008717
10202344041401
11788a4a331a7
123327073a221
1316108b44518
149b17535c25
1553e41450a1
hex2f1ca50bb9

202344041401 has 2 divisors, whose sum is σ = 202344041402. Its totient is φ = 202344041400.

The previous prime is 202344041387. The next prime is 202344041423. The reversal of 202344041401 is 104140443202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 189465196176 + 12878845225 = 435276^2 + 113485^2 .

It is a cyclic number.

It is not a de Polignac number, because 202344041401 - 25 = 202344041369 is a prime.

It is a super-2 number, since 2×2023440414012 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (202344044401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101172020700 + 101172020701.

It is an arithmetic number, because the mean of its divisors is an integer number (101172020701).

Almost surely, 2202344041401 is an apocalyptic number.

It is an amenable number.

202344041401 is a deficient number, since it is larger than the sum of its proper divisors (1).

202344041401 is an equidigital number, since it uses as much as digits as its factorization.

202344041401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 202344041401 its reverse (104140443202), we get a palindrome (306484484603).

The spelling of 202344041401 in words is "two hundred two billion, three hundred forty-four million, forty-one thousand, four hundred one".