Base | Representation |
---|---|
bin | 10010110110100001… |
… | …100010001110011001 |
3 | 1221020201002220102221 |
4 | 102312201202032121 |
5 | 312423440112213 |
6 | 13144334424041 |
7 | 1314422060653 |
oct | 226641421631 |
9 | 57221086387 |
10 | 20242113433 |
11 | 8648166473 |
12 | 3b0b062021 |
13 | 1ba78b8719 |
14 | da050b6d3 |
15 | 7d714338d |
hex | 4b6862399 |
20242113433 has 2 divisors, whose sum is σ = 20242113434. Its totient is φ = 20242113432.
The previous prime is 20242113413. The next prime is 20242113449. The reversal of 20242113433 is 33431124202.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20239899289 + 2214144 = 142267^2 + 1488^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20242113433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20242113398 and 20242113407.
It is not a weakly prime, because it can be changed into another prime (20242113413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10121056716 + 10121056717.
It is an arithmetic number, because the mean of its divisors is an integer number (10121056717).
Almost surely, 220242113433 is an apocalyptic number.
It is an amenable number.
20242113433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20242113433 is an equidigital number, since it uses as much as digits as its factorization.
20242113433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 20242113433 its reverse (33431124202), we get a palindrome (53673237635).
The spelling of 20242113433 in words is "twenty billion, two hundred forty-two million, one hundred thirteen thousand, four hundred thirty-three".
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