202433141113 has 4 divisors (see below), whose sum is σ = 231352161280. Its totient is φ = 173514120948.

The previous prime is 202433141111. The next prime is 202433141173. The reversal of 202433141113 is 311141334202.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311141334202 = 2 ⋅155570667101.

It is not a de Polignac number, because 202433141113 - 2¹ = 202433141111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (202433141111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14459510073 + ... + 14459510086.

It is an arithmetic number, because the mean of its divisors is an integer number (57838040320).

Almost surely, 2^202433141113 is an apocalyptic number.

It is an amenable number.

202433141113 is a deficient number, since it is larger than the sum of its proper divisors (28919020167).

202433141113 is an equidigital number, since it uses as much as digits as its factorization.

202433141113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28919020166.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 202433141113 its reverse (311141334202), we get a palindrome (513574475315).

The spelling of 202433141113 in words is "two hundred two billion, four hundred thirty-three million, one hundred forty-one thousand, one hundred thirteen".