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20250241131 = 313679493463
BaseRepresentation
bin10010110111000000…
…100010100001101011
31221021021101211112210
4102313000202201223
5312433030204011
613145224540203
71314551131611
oct226700424153
957237354483
1020250241131
11865180797a
123b11921663
131ba94a3003
14da16256b1
157d7beb6a6
hex4b702286b

20250241131 has 8 divisors (see below), whose sum is σ = 27002350080. Its totient is φ = 13499146472.

The previous prime is 20250241103. The next prime is 20250241139. The reversal of 20250241131 is 13114205202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20250241131 - 217 = 20250110059 is a prime.

It is a super-2 number, since 2×202502411312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20250241098 and 20250241107.

It is not an unprimeable number, because it can be changed into a prime (20250241139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 205695 + ... + 287768.

It is an arithmetic number, because the mean of its divisors is an integer number (3375293760).

Almost surely, 220250241131 is an apocalyptic number.

20250241131 is a deficient number, since it is larger than the sum of its proper divisors (6752108949).

20250241131 is a wasteful number, since it uses less digits than its factorization.

20250241131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 507145.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 20250241131 its reverse (13114205202), we get a palindrome (33364446333).

The spelling of 20250241131 in words is "twenty billion, two hundred fifty million, two hundred forty-one thousand, one hundred thirty-one".

Divisors: 1 3 13679 41037 493463 1480389 6750080377 20250241131