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20251214013977 is a prime number
BaseRepresentation
bin1001001101011000110100…
…11010101110011000011001
32122200222220220221122212122
410212230122122232120121
510123243441241421402
6111023140154151025
74160046650634662
oct446543232563031
978628826848778
1020251214013977
1164a85453a9a21
1223309a2722475
13b3b8b1a3299b
14500241daa369
15251ba9557ca2
hex126b1a6ae619

20251214013977 has 2 divisors, whose sum is σ = 20251214013978. Its totient is φ = 20251214013976.

The previous prime is 20251214013889. The next prime is 20251214014069. The reversal of 20251214013977 is 77931041215202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17015493000256 + 3235721013721 = 4124984^2 + 1798811^2 .

It is a cyclic number.

It is not a de Polignac number, because 20251214013977 - 214 = 20251213997593 is a prime.

It is a super-2 number, since 2×202512140139772 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20251214013077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10125607006988 + 10125607006989.

It is an arithmetic number, because the mean of its divisors is an integer number (10125607006989).

Almost surely, 220251214013977 is an apocalyptic number.

It is an amenable number.

20251214013977 is a deficient number, since it is larger than the sum of its proper divisors (1).

20251214013977 is an equidigital number, since it uses as much as digits as its factorization.

20251214013977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 211680, while the sum is 44.

The spelling of 20251214013977 in words is "twenty trillion, two hundred fifty-one billion, two hundred fourteen million, thirteen thousand, nine hundred seventy-seven".