Base | Representation |
---|---|
bin | 11101011110010011011… |
… | …011011111100101000011 |
3 | 21011121220211011201110212 |
4 | 131132103123133211003 |
5 | 231141011140220103 |
6 | 4150242440344335 |
7 | 266221242622121 |
oct | 35362333374503 |
9 | 7147824151425 |
10 | 2025403054403 |
11 | 710a72249623 |
12 | 2886534750ab |
13 | 118cc143b501 |
14 | 7005c594911 |
15 | 37a432687d8 |
hex | 1d7936df943 |
2025403054403 has 2 divisors, whose sum is σ = 2025403054404. Its totient is φ = 2025403054402.
The previous prime is 2025403054391. The next prime is 2025403054429. The reversal of 2025403054403 is 3044503045202.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2025403054403 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2025403054403.
It is not a weakly prime, because it can be changed into another prime (2025403054483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1012701527201 + 1012701527202.
It is an arithmetic number, because the mean of its divisors is an integer number (1012701527202).
Almost surely, 22025403054403 is an apocalyptic number.
2025403054403 is a deficient number, since it is larger than the sum of its proper divisors (1).
2025403054403 is an equidigital number, since it uses as much as digits as its factorization.
2025403054403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 32.
Adding to 2025403054403 its reverse (3044503045202), we get a palindrome (5069906099605).
The spelling of 2025403054403 in words is "two trillion, twenty-five billion, four hundred three million, fifty-four thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •