Base | Representation |
---|---|
bin | 1001001101011110101100… |
… | …01111101011100000101011 |
3 | 2122201022001112112021210101 |
4 | 10212233112033223200223 |
5 | 10123321420000011433 |
6 | 111024421003530231 |
7 | 4160221023604666 |
oct | 446572617534053 |
9 | 78638045467711 |
10 | 20254365235243 |
11 | 64a9912166117 |
12 | 2331521b29977 |
13 | b3bc94852c59 |
14 | 5004606d86dd |
15 | 251ce101d07d |
hex | 126bd63eb82b |
20254365235243 has 2 divisors, whose sum is σ = 20254365235244. Its totient is φ = 20254365235242.
The previous prime is 20254365235217. The next prime is 20254365235249. The reversal of 20254365235243 is 34253256345202.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20254365235243 - 29 = 20254365234731 is a prime.
It is a super-2 number, since 2×202543652352432 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20254365235193 and 20254365235202.
It is not a weakly prime, because it can be changed into another prime (20254365235249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10127182617621 + 10127182617622.
It is an arithmetic number, because the mean of its divisors is an integer number (10127182617622).
Almost surely, 220254365235243 is an apocalyptic number.
20254365235243 is a deficient number, since it is larger than the sum of its proper divisors (1).
20254365235243 is an equidigital number, since it uses as much as digits as its factorization.
20254365235243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184000, while the sum is 46.
The spelling of 20254365235243 in words is "twenty trillion, two hundred fifty-four billion, three hundred sixty-five million, two hundred thirty-five thousand, two hundred forty-three".
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