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202554145193 is a prime number
BaseRepresentation
bin1011110010100100101…
…0101111100110101001
3201100211100100201000112
42330221022233212221
511304312330121233
6233015130144105
720430323553311
oct2745112574651
9640740321015
10202554145193
11789a25972a4
123330ab82035
13161405286aa
149b373c8441
1554077e8048
hex2f292af9a9

202554145193 has 2 divisors, whose sum is σ = 202554145194. Its totient is φ = 202554145192.

The previous prime is 202554145181. The next prime is 202554145229. The reversal of 202554145193 is 391541455202.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117764276224 + 84789868969 = 343168^2 + 291187^2 .

It is a cyclic number.

It is not a de Polignac number, because 202554145193 - 220 = 202553096617 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 202554145193.

It is not a weakly prime, because it can be changed into another prime (202554147193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 101277072596 + 101277072597.

It is an arithmetic number, because the mean of its divisors is an integer number (101277072597).

Almost surely, 2202554145193 is an apocalyptic number.

It is an amenable number.

202554145193 is a deficient number, since it is larger than the sum of its proper divisors (1).

202554145193 is an equidigital number, since it uses as much as digits as its factorization.

202554145193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 41.

The spelling of 202554145193 in words is "two hundred two billion, five hundred fifty-four million, one hundred forty-five thousand, one hundred ninety-three".