Base | Representation |
---|---|
bin | 1001001110110100011111… |
… | …01000100011100001101001 |
3 | 2122212200221112111122102122 |
4 | 10213122033220203201221 |
5 | 10130100232323322212 |
6 | 111101515301041025 |
7 | 4163441314142342 |
oct | 447321750434151 |
9 | 78780845448378 |
10 | 20300425214057 |
11 | 65173a8890a0a |
12 | 233a4373b6175 |
13 | b434252416a1 |
14 | 50278da490c9 |
15 | 2530d9a39272 |
hex | 12768fa23869 |
20300425214057 has 2 divisors, whose sum is σ = 20300425214058. Its totient is φ = 20300425214056.
The previous prime is 20300425214051. The next prime is 20300425214107. The reversal of 20300425214057 is 75041252400302.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14028350757136 + 6272074456921 = 3745444^2 + 2504411^2 .
It is a cyclic number.
It is not a de Polignac number, because 20300425214057 - 28 = 20300425213801 is a prime.
It is not a weakly prime, because it can be changed into another prime (20300425214051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10150212607028 + 10150212607029.
It is an arithmetic number, because the mean of its divisors is an integer number (10150212607029).
Almost surely, 220300425214057 is an apocalyptic number.
It is an amenable number.
20300425214057 is a deficient number, since it is larger than the sum of its proper divisors (1).
20300425214057 is an equidigital number, since it uses as much as digits as its factorization.
20300425214057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 67200, while the sum is 35.
Adding to 20300425214057 its reverse (75041252400302), we get a palindrome (95341677614359).
The spelling of 20300425214057 in words is "twenty trillion, three hundred billion, four hundred twenty-five million, two hundred fourteen thousand, fifty-seven".
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