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2030301101113 = 29689910147903
BaseRepresentation
bin11101100010110111011…
…000000011110000111001
321012002120011201021102021
4131202313120003300321
5231231024040213423
64152412450434441
7266453516420515
oct35426730036071
97162504637367
102030301101113
1171305605060a
1228959b892a21
131195c21214bc
14703a4cb7145
1537c2d28195d
hex1d8b7603c39

2030301101113 has 8 divisors (see below), whose sum is σ = 2100616128000. Its totient is φ = 1960006383888.

The previous prime is 2030301101107. The next prime is 2030301101131. The reversal of 2030301101113 is 3111011030302.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2030301101113 is a prime.

It is a super-2 number, since 2×20303011011132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2030301101513) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4873881 + ... + 5274022.

It is an arithmetic number, because the mean of its divisors is an integer number (262577016000).

Almost surely, 22030301101113 is an apocalyptic number.

It is an amenable number.

2030301101113 is a deficient number, since it is larger than the sum of its proper divisors (70315026887).

2030301101113 is a wasteful number, since it uses less digits than its factorization.

2030301101113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10154831.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 2030301101113 its reverse (3111011030302), we get a palindrome (5141312131415).

The spelling of 2030301101113 in words is "two trillion, thirty billion, three hundred one million, one hundred one thousand, one hundred thirteen".

Divisors: 1 29 6899 200071 10147903 294289187 70010382797 2030301101113