20303331343441 has 4 divisors (see below), whose sum is σ = 20303784153072. Its totient is φ = 20302878533812.

The previous prime is 20303331343411. The next prime is 20303331343513. The reversal of 20303331343441 is 14434313330302.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20303331343441 - 2¹⁵ = 20303331310673 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20303331343397 and 20303331343406.

It is not an unprimeable number, because it can be changed into a prime (20303331343411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226337551 + ... + 226427236.

It is an arithmetic number, because the mean of its divisors is an integer number (5075946038268).

Almost surely, 2^{20303331343441} is an apocalyptic number.

It is an amenable number.

20303331343441 is a deficient number, since it is larger than the sum of its proper divisors (452809631).

20303331343441 is an equidigital number, since it uses as much as digits as its factorization.

20303331343441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 452809630.

The product of its (nonzero) digits is 93312, while the sum is 34.

Adding to 20303331343441 its reverse (14434313330302), we get a palindrome (34737644673743).

The spelling of 20303331343441 in words is "twenty trillion, three hundred three billion, three hundred thirty-one million, three hundred forty-three thousand, four hundred forty-one".